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4l^2+7l-135=0
a = 4; b = 7; c = -135;
Δ = b2-4ac
Δ = 72-4·4·(-135)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$l_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$l_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$l_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-47}{2*4}=\frac{-54}{8} =-6+3/4 $$l_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+47}{2*4}=\frac{40}{8} =5 $
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